-5.X^2+20x=-5

Solution for -5.X^2+20x=-5 equation:

-5.X^2+20X=-5

We move all terms to the left:

-5.X^2+20X-(-5)=0

We add all the numbers together, and all the variables

-5X^2+20X+5=0

a = -5; b = 20; c = +5;
Δ = b2-4ac
Δ = 202-4·(-5)·5
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{5}}{2*-5}=\frac{-20-10\sqrt{5}}{-10}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{5}}{2*-5}=\frac{-20+10\sqrt{5}}{-10}
$